Question

(a-3)×(a+4)>(a+5)×(a-4)

Answer 1

Ответ:

Это правильно 100%!!!!!!!!

Answer 2

To solve the inequality $(a-3) \cdot (a+4) > (a+5) \cdot (a-4)$, we can start by expanding both sides of the inequality and simplifying:

$(a-3) \cdot (a+4) > (a+5) \cdot (a-4)$

Expand the left side:

$a^2 + 4a - 3a - 12 > (a+5) \cdot (a-4)$

Simplify the left side:

$a^2 + a - 12 > (a+5) \cdot (a-4)$

Now, let's further simplify the right side by multiplying the two binomials:

$a^2 + a - 12 > (a^2 + 5a - 4a - 20)$

Now, distribute the values on the right side:

$a^2 + a - 12 > a^2 + a - 20$

Notice that the $a^2$ and $a$ terms cancel out on both sides:

$-12 > -20$

Now, you can see that the inequality is true for all real values of $a$ because $-12$ is indeed greater than $-20$. Therefore, the solution to the inequality is:

$-12 > -20$

This means that the inequality $(a-3) \cdot (a+4) > (a+5) \cdot (a-4)$ is satisfied for all real values of $a$.