Question

(50-32)-x 300+(x-100) X<41 x>25 X+47=100 90-x=12

Answer 1

Ответ:

(50-32)-x

300+(x-100)

x<41

x>25

x+47=100

90-x=12

Пошаговое объяснение:

Можно лудший ответ)?

Answer 2

Let's solve the given system of equations step by step:

1. $50 - 32 - x = 300 + (x - 100)$ (Equation 1) Simplify Equation 1: $-x + 18 = 300 + x - 100$ $-x + 18 = 200 + x$

2. $x < 41$ (Equation 2)

3. $x > 25$ (Equation 3)

4. $x + 47 = 100$ (Equation 4) Solve for $x$ in Equation 4: $x = 100 - 47$ $x = 53$

5. $90 - x = 12$ (Equation 5) Solve for $x$ in Equation 5: $90 - x = 12$ $x = 90 - 12$ $x = 78$

Now, let's determine the valid values of $x$ that satisfy the given conditions (Equations 2, 3, and 5):

• $x < 41$: This condition is satisfied for $x = 53$ (from Equation 4).

• $x > 25$: This condition is satisfied for $x = 53$ (from Equation 4).

• $x = 78$ (from Equation 5).

So, the valid values of $x$ that satisfy the given conditions are $x = 53$ and $x = 78$.