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{5(х+2у)-3=3х+5 {4(х-3у)-50=-33у Смотреть ответ vasilinapipak vasilinapipak Пошаговое объяснение: {5(х+2у)-3=3х+5 {4(х-3у)-50=-33у {x=4-5y {4(x-3y) -50= -33y 4(4-5y-3y)-50=-33y y=34 x= 4-5×34 x= -166 (x,y)= (-166;34) Перевіряємо розв'язок: {5(-166+2×34) -3= 3× (-166)+5 { 4(-166-3×34) -50= -33× 34 { -493= -493 {-1122= -1122 Відповідь: (x,y) = (-166, 34). Новые вопросы в Математика Розв'яжiть завдання ( 1 бал) 2.1 Знайдіть гострі кути прямокутного трикутника ABC, якщо кут С = 90°,AB = 6, СB =3. 2.2 Знайдіть суму кутів опуклого се … микутника. 2.3 Обчисліть: 4 cos 60º - 5sin30º.tg 45ºдопоможіть будь ласка, дуже потрібно​ 1.6 Знайдіть площу ромба, діагоналі якого становлять 6 см і 4 см. B. 24 см² A.10 см² Б. 12 см² A Б B Г Частина друга Г.48 см²​ 1.4 Периметр рівнобічної трапеції, описаної навколо кола, становить 40 см. Знайдіть бічну сторону трапеції. A.5 см B. 15 см Г.20 см ​ 1.3 Знайдіть периметр трикутника, якщо його середні лінії становлять 4см, 6 см і 8 см Г.36 см А.9 см Б. 15 см В. 18 см ​ Оберіть правильну відповідь (0,5 бали) 1.1Функцію задано формулою f(x) = 4x - 27 Якщо x=(-12). A. 26 Б.-45 B. - 75 A 13 П Б B r г. - 15,78​ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Давайте рассмотрим задачи по очереди:

2.1 Знайдіть гострі кути прямокутного трикутника ABC, якщо кут С = 90°, AB = 6, і CB = 3.

Так как у вас есть прямоугольный треугольник (с углом в 90°), вы можете использовать теорему Пифагора для нахождения оставшихся сторон. Пусть A - это вершина прямого угла. Тогда:

AC^2 + BC^2 = AB^2

где AC и BC - катеты, а AB - гипотенуза.

AC^2 + 3^2 = 6^2 AC^2 + 9 = 36 AC^2 = 36 - 9 AC^2 = 27 AC = √27 AC = 3√3

Теперь, чтобы найти гострые углы, вы можете использовать тригонометрические функции. Например, синус угла A можно найти как:

sin(A) = BC / AB sin(A) = 3 / 6 sin(A) = 1/2

Таким образом, A = arcsin(1/2) ≈ 30°.

Угол B равен 90° - угол A, то есть 90° - 30° = 60°.

Итак, гострые углы треугольника ABC равны 30° и 60°.

2.2 Знайдіть суму кутів опуклого семикутника.

Сума всех внутренних углов опуклого семикутника равна (7 - 2) * 180° = 5 * 180° = 900°.

2.3 Обчисліть: 4 cos 60º - 5sin 30º * tg 45º.

Давайте вычислим каждую часть выражения по отдельности:

cos(60°) = 1/2 sin(30°) = 1/2 tg(45°) = 1

Теперь вы можете подставить эти значения в вашу формулу:

4 * (1/2) - 5 * (1/2) * 1 = 2 - 5/2 = 4/2 - 5/2 = -1/2

Ответ: -1/2.

1.6 Знайдіть площу ромба, діагоналі якого становлять 6 см і 4 см.

Площадь ромба можно найти, используя формулу:

Площадь = (первая диагональ * вторая диагональ) / 2

Площадь = (6 см * 4 см) / 2 = (24 см²) / 2 = 12 см².

Ответ: 12 см².

1.4 Периметр рівнобічної трапеції, описаної навколо кола, становить 40 см. Знайдіть бічну сторону трапеції.

Рассмотрим рівнобічну трапецію, описану вокруг круга. Периметр такой трапеции можно представить как сумму длин всех ее сторон.

Давайте обозначим:

P - периметр трапеции r - радиус вписанного круга

Тогда P = 2a + 2b, где a и b - это боковые стороны трапеции. Так как трапеция рівнобічна, то a = b.

P = 2a + 2a = 4a

Также известно, что периметр трапеции составляет 40 см, то есть:

4a = 40

Теперь найдем длину одной из сторон:

a = 40 / 4 = 10 см

Так как a = b, то длина боковой стороны трапеции равна 10 см.

Ответ: боковая сторона трапеции равна 10 см.