Question

(4(3x + y) - 1 = y 22,2(4x - y) +19 = -3;​

Answer 1

Ответ:

Пошаговое объяснение:

(4(3x+y))-1=22y

3x+y-22y=-4+1

4y-22y=-3

-18y=-3

y=-18:(-3)

y=-6

Answer 2

It looks like you have a system of two linear equations with two variables, x and y. You can solve this system of equations using various methods, such as substitution, elimination, or matrices. I'll use the elimination method to solve this system:

1. First, let's write the system of equations:

   4(3x + y) - 1 = 22 2(4x - y) + 19 = -3

2. Expand and simplify the equations:

   12x + 4y - 1 = 22 8x - 2y + 19 = -3

3. Bring like terms to one side of each equation:

   12x + 4y = 22 + 1 8x - 2y = -3 - 19

4. Further simplify the equations:

   12x + 4y = 23 8x - 2y = -22

5. Now, we'll eliminate one of the variables. To do that, we can multiply the second equation by 2 to make the coefficients of y in both equations cancel out when we add them:

   12x + 4y = 23 16x - 4y = -44

6. Add the two equations together to eliminate the variable y:

   (12x + 16x) + (4y - 4y) = 23 - 44 28x = -21

7. Now, solve for x:

   28x = -21 x = -21 / 28 x = -3/4

8. With the value of x, you can now substitute it into one of the original equations to find the value of y. I'll use the first equation:

   12x + 4y = 23 12(-3/4) + 4y = 23 -9 + 4y = 23

9. Solve for y:

   4y = 23 + 9 4y = 32 y = 32 / 4 y = 8

So, the solution to the system of equations is: x = -3/4 y = 8