Question

0,3х(х-2)-0,2(х+4)=0,6​

Answer 1

Ответ:

х=5

Пошаговое объяснение:

0,6х-0,6-0,2х-0,8=0,6

0,4х=2

х=5

Answer 2

To solve the given equation $0.3x(x-2) - 0.2(x+4) = 0.6$, we'll follow these steps:

1. Distribute the constants and simplify the equation.
2. Expand and simplify the expression.
3. Solve for $x$.

Let's proceed with these steps:

Step 1: $0.3x(x-2) - 0.2(x+4) = 0.6$

Step 2: $0.3x^2 - 0.6x - 0.2x - 0.8 = 0.6$

Step 3: $0.3x^2 - 0.8x - 0.8 = 0.6$

Now, let's move all terms to one side to set the quadratic equation to zero:

$0.3x^2 - 0.8x - 1.4 = 0$

Now, we have a quadratic equation in the form $ax^2 + bx + c = 0$, where $a = 0.3$, $b = -0.8$, and $c = -1.4$. We can solve this using the quadratic formula:

The quadratic formula is:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Plugging in the values, we get:

$x = \frac{-(-0.8) \pm \sqrt{(-0.8)^2 - 4 \times 0.3 \times (-1.4)}}{2 \times 0.3}$

Solving this will give us the values of $x$. Let's proceed with the calculations:

$x = \frac{0.8 \pm \sqrt{0.64 + 1.68}}{0.6}$

$x = \frac{0.8 \pm \sqrt{2.32}}{0.6}$

Now, let's calculate the two possible values for $x$ using the plus and minus signs:

$x_1 = \frac{0.8 + \sqrt{2.32}}{0.6}$

$x_2 = \frac{0.8 - \sqrt{2.32}}{0.6}$

These will be the solutions for the given equation. Let's calculate the numerical values for $x_1$ and $x_2$.