Question

D(4;-5) F(-3;-1) |DF| -?​

Answer 1

Ответ:

D(4;-5) F(-3;-1)

|DDF=√(x2-x1)²+(y2-y1)²

√(-3-4)²+(-1+5)²=

√49+16=√65

Answer 2

To find the distance between two points D(4, -5) and F(-3, -1), you can use the distance formula:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

In this case:

x1 = 4 y1 = -5 x2 = -3 y2 = -1

Distance = √((-3 - 4)^2 + (-1 - (-5))^2) Distance = √((-7)^2 + (4)^2) Distance = √(49 + 16) Distance = √65

So, the distance |DF| between points D(4, -5) and F(-3, -1) is √65 (approximately 8.06 units).