Question

-4 (5-2m) + 3 (m-4) = 6 (2-m) - 5m

Answer 1

Ответ:

-4 (5-2m) + 3 (m-4) = 6 (2-m) - 5m

-20+8m+3m-12=12-6m-5m

8m+3m+6m+5m=12+12+20

22m=44

m=44/22

m=2

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-4(5-2*2)+3(2-4)=6(2-2)-5*2

-4+(-6)=6*0-10

-10=-10

Пошаговое объяснение:

Answer 2

Ответ:

Пошаговое объяснение:

-20 + 8m + 3m - 12 = 12 - 6m - 5m

8m + 3m + 6m + 5m = 12 + 20 + 12

22m = 44

m = 44 : 22

m = 2

Answer 3

To solve the equation -4(5-2m) + 3(m-4) = 6(2-m) - 5m, you can follow these steps:

1. Distribute the constants on both sides of the equation:

-4 * 5 + (-4) * (-2m) + 3 * m + 3 * (-4) = 6 * 2 + 6 * (-m) - 5m

Now, simplify each term:

-20 + 8m + 3m - 12 = 12 - 6m - 5m

2. Combine like terms on each side:

8m + 3m - 20 - 12 = 12 - 6m - 5m

11m - 32 = 12 - 11m

3. Add 11m to both sides to get the variable terms on one side of the equation:

11m + 11m - 32 = 12 - 11m + 11m

22m - 32 = 12

4. Add 32 to both sides to isolate the variable term:

22m - 32 + 32 = 12 + 32

22m = 44

5. Finally, divide both sides by 22 to solve for m:

(22m)/22 = 44/22

m = 2

So, the solution to the equation is m = 2.