Question

на трёх овощных базах было 2600ц овощей. Когда с первой базы увезли 270 ц,со второй-780ц,а с третьей - 590 ц, то на всех трёх овощных базах стало овощей поровну. Сколько центнеров овощей было на каждой базе? ​

Answer 1

Ответ:

590 ц, 1100 ц, 910ц

Пошаговое объяснение:

2600-(270+780+590)=960 ц

960:3=320 ц

320+270= 590 ц (первая база)

320+780= 1100 ц (вторая база)

320+590= 910 ц (третья база)

Answer 2

To solve this problem, we can set up a system of equations. Let's denote the number of centners of vegetables on the first base as x, on the second base as y, and on the third base as z.

According to the given information, the total number of centners of vegetables on the three bases is 2600 centners. So we have the equation:

x + y + z = 2600 ---(1)

We also know that when 270 centners were taken from the first base, 780 centners were taken from the second base, and 590 centners were taken from the third base, the remaining vegetables on all three bases were equal. This gives us two more equations:

x - 270 = y - 780 ---(2) x - 270 = z - 590 ---(3)

To solve this system of equations, we can use the method of substitution or elimination. Let's use the method of substitution.

From equation (2), we can express y in terms of x: y = x - 270 + 780 y = x + 510 ---(4)

From equation (3), we can express z in terms of x: z = x - 270 + 590 z = x + 320 ---(5)

Now, substitute equations (4) and (5) into equation (1):

x + (x + 510) + (x + 320) = 2600 3x + 830 = 2600 3x = 2600 - 830 3x = 1770 x = 1770 / 3 x = 590

Substitute the value of x back into equations (4) and (5) to find y and z:

y = 590 + 510 y = 1100

z = 590 + 320 z = 910

Therefore, there were 590 centners of vegetables on the first base, 1100 centners on the second base, and 910 centners on the third base.