Question

Tg(2pi-x)cos(3pi/2+2x)=sin(-pi/2)

Answer 1

Пытался попонятнее, последнее это ответ (объединение)

Answer 2

Let's solve the equation step by step:

Tg(2π - x) * cos(3π/2 + 2x) = sin(-π/2)

First, let's simplify the equation by substituting the trigonometric functions:

tan(2π - x) * cos(3π/2 + 2x) = sin(-π/2)

Next, we'll replace the trigonometric functions with their corresponding identities:

tan(2π - x) = sin(2π - x) / cos(2π - x) cos(3π/2 + 2x) = cos(π/2 - (3π/2 + 2x)) sin(-π/2) = -1

Now we have:

sin(2π - x) / cos(2π - x) * cos(π/2 - (3π/2 + 2x)) = -1

Next, let's simplify further:

sin(2π - x) / cos(2π - x) * cos(π/2 - 3π/2 - 2x) = -1 sin(2π - x) / cos(2π - x) * cos(-π/2 - 2x) = -1

Since cos(-θ) =