Question

( базовый уровень)log 5( log 2 32)= ......

Answer 1

$log_{5}(log_{2}32) =log_{5}(log_{2}2^{5}) =log_{5}5=1$

Answer 2

Log5(log2 32)=log5 5=1

Answer 3

To simplify the expression log₅(log₂32), let's break it down step by step:

First, we need to find the value of log₂32. This represents the power to which we need to raise 2 to obtain 32. In other words, we need to find the exponent x in the equation 2^x = 32.

Since 2^5 = 32, we can conclude that log₂32 = 5.

Now, we can substitute the value of log₂32 into the original expression:

log₅(log₂32) = log₅5

The logarithm base 5 of 5 is equal to 1, so the simplified expression is:

log₅(log₂32) = 1