Question

(1-2√3)^2+4√3(√3+1) решите

Answer 1

${(1 - 2 \sqrt{3}) }^{2} + 4 \sqrt{3} ( \sqrt{3 } + 1 ) = (1 -4 \sqrt{3} + 4 \times 3) + (4 \times 3 + 4 \sqrt{3} ) = 1 + 12 + 12 = 25$

Answer 2

Ответ:

25.

Пошаговое объяснение:

(1-2√3)^2+4√3(√3+1) = 1^2 -2•2√3•1 + (2√3)^2 +4√3•√3 + 4√3 = 1 - 4√3 + 12 + 12 + 4√3 = 25.

Использована формула

(а - b)^2 = a^2 - 2ab + b^2.

Answer 3

To solve this expression, we'll first expand the expression in the first set of parentheses:

(1 - 2√3)^2 = (1 - 2√3)(1 - 2√3) = 1 - 2√3 - 2√3 + 12 = 13 - 4√3

Next, we'll expand the expression in the second set of parentheses:

4√3(√3 + 1) = 4√3 × √3 + 4√3 × 1 = 12 + 4√3

Now, we can combine these two expressions:

(1 - 2√3)^2 + 4√3(√3 + 1) = (13 - 4√3) + (12 + 4√3) = 25

Therefore, the solution is 25.