Question

Выполните действия:б)m/m-n+m/m+n;в)4x/x^2-y^2-4/x+y;г)5a/a-5+25/5-a.Все!

Answer 1

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Answer 2

а) m/m-n + m/m+n = (m^2 + mn + m^2 - mn)/(m^2 - n^2) = 2m^2/(m^2 - n^2)

б) 4x/(x^2 - y^2) - 4/(x + y) = (4x - 4(x - y))/(x^2 - y^2)(x + y) = 4y/(x^2 - y^2)(x + y)

г) 5a/(a - 5) + 25/(5 - a) = (-5a + 25 + 5a)/(a^2 - 25) = 25/(a^2 - 25) = 25/((a - 5)(a + 5))