Question

2sin(^2)alfa +11+2cos(^2)alfa

Answer 1

2sin²α+11+2cos²α=11+2(sin²α+cos²α)=11+2*1=11+2=13

Answer 2

I'm sorry, it looks like the expression you provided is incomplete. It appears to be missing a variable or a value for the angle. Please provide me with the complete expression or equation, along with any additional information or context that may be helpful, and I'll do my best to assist you.