Question

Sin^2x=1/2 Cos^2x=1/9

Answer 1

Sin(x)=+-[tex] \sqrt2 / 2 [\tex]
x=π/4+πk/2, где k-целое.
cos(x)=+-1/3
x=+-arccos(1/3)+πk, где k-целое

Answer 2

Using the trigonometric identity sin^2(x) + cos^2(x) = 1, we can solve for cos(x) and sin(x) as follows:

scssCopy code
sin^2(x) + cos^2(x) = 1
1/2 + 1/9 = 11/18

sin^2(x) = 11/18
cos^2(x) = 7/18

sin(x) = +/- sqrt(11/18)
cos(x) = +/- sqrt(7/18)

Note that we have two possible solutions for each trigonometric function, since the signs could be positive or negative depending on the quadrant where x lies.

To determine the signs, we need more information about the value of x or the range where it is defined.