Question

Y=(x² + 1)(x-2)................ ​

Answer 1

Ответ: х= 2.

y=(x² + 1)(x-2)

подставляем у=0

0=(х²+1)·(х-2)

решается относительно х

х= 2.

Answer 2

To expand the expression Y=(x² + 1)(x-2), we can use the distributive property of multiplication:

Y = x²(x - 2) + 1(x - 2)

Now, we can simplify each term separately:

x²(x - 2) = x³ - 2x² 1(x - 2) = x - 2

Putting the two terms back together, we get:

Y = x³ - 2x² + x - 2

So the expanded form of Y=(x² + 1)(x-2) is Y = x³ - 2x² + x - 2.