Question

F(x)=cos x+3sin x M(П;2)

Answer 1

F(x)=cosx+3sinx
f(π/2)=cos(π/2)+3sin(π/2)=0+3*1=3
f'(x)=-sinx+3cosx
f'(π/2)=-sinπ/2+cosπ/2=-1

Answer 2

To find the value of F(x) at x=π and y=2, we substitute these values into the expression for F(x):

F(π) = cos(π) + 3sin(π) = -1 + 0 = -1 So, F(π;2) = (-1, 2).

Therefore, the value of F(x) at x=π and y=2 is (-1, 2).