Question

Mn-2n-3m+6 разложить на множители

Answer 1

mn-2n-3m+6= (mn-2n)-(3n -6)= n(m-2)-3(m-2)=(n-3)(m-2)

Answer 2

 (mn-2n)-(3n -6)= n(m-2)-3(m-2)=(n-3)(m-2)

Answer 3

To factorize the expression Mn-2n-3m+6, we can look for common factors and grouping.

Let's group the terms with similar variables:

Mn - 2n - 3m + 6

Taking out the common factor from the first two terms, n, we get:

n(M - 2) - 3m + 6

Now, we can observe that the last two terms have a common factor of 3:

n(M - 2) - 3(m - 2)

Notice that the expression (M - 2) appears in both terms. We can factor it out as well:

n(M - 2) - 3(m - 2) = (M - 2)(n - 3)

Therefore, the factored form of Mn-2n-3m+6 is (M - 2)(n - 3).