Question

A2+b2-2ab при a=7 b=5

Answer 1

A^2+b^2-2ab=(a-b)^2. подставляем значения: (7-5)^2=2^2=4.

Answer 2

To evaluate the expression A^2 + B^2 - 2AB when A = 7 and B = 5, we substitute the values into the expression:

A^2 + B^2 - 2AB = 7^2 + 5^2 - 2 * 7 * 5 = 49 + 25 - 2 * 7 * 5 = 49 + 25 - 70 = 74 - 70 = 4

Therefore, when A = 7 and B = 5, the value of A^2 + B^2 - 2AB is 4.