
(Х-2)*(Х*Х+8Х+16)=7(Х+4)


Ответы на вопрос

(х-2)(х²+8х+16) - 7(х+4)=0
(х-2)(х+4)²-7(х+4)=0
(х+4)((х+2)(х+4)-7)=0
х+4 =0 или (х-2)(х+4)-7=0
х=-4 х²+2х-15=0
х=-5,х=3
Ответ: -4;-5;3.



To solve the equation (x - 2)(x^2 + 8x + 16) = 7(x + 4)
, we'll start by simplifying both sides of the equation and then solving for x.
Expanding the terms on the left side:
(x - 2)(x^2 + 8x + 16) = 7(x + 4) x(x^2 + 8x + 16) - 2(x^2 + 8x + 16) = 7x + 28
Now let's simplify further:
x^3 + 8x^2 + 16x - 2x^2 - 16x - 32 = 7x + 28 x^3 + 6x^2 - 7x - 32 = 7x + 28
Combining like terms:
x^3 + 6x^2 - 7x - 7x - 32 - 28 = 0 x^3 + 6x^2 - 14x - 60 = 0
Now we need to solve this cubic equation. Unfortunately, cubic equations don't have a general formula like quadratics do. We can either try to factor the equation or use numerical methods to approximate the roots.
By observing the equation, we can see that x = 2 is a root (since (x - 2) appears as a factor in the original equation). We can use long division or synthetic division to divide the equation by (x - 2):
Dividing x^3 + 6x^2 - 14x - 60 by (x - 2):
markdown x^2 + 8x + 30
___________________
x - 2 | x^3 + 6x^2 - 14x - 60 - (x^3 - 2x^2) _______________ 8x^2 - 14x - (8x^2 - 16x) _______________ 2x - 60 - (2x - 4) ___________ -56
The quotient is x^2 + 8x + 30, and the remainder is -56.
So, we have:
(x^3 + 6x^2 - 14x - 60) / (x - 2) = x^2 + 8x + 30 - (56 / (x - 2))
Now, the equation becomes:
x^2 + 8x + 30 - (56 / (x - 2)) = 0
To solve this equation, we can either use numerical methods or approximate the solutions graphically. Unfortunately, I can't provide the exact solutions without numerical methods.


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