Question

2^2-x=16 4^1-2x=64 2^1-x=8

Answer 1

Х=16-4
х=12
...
-2х=64-4
-х=30
х=-30
...

Answer 2

1) 2^2-x=16
4-x=16
-x = 16-4
-x = 12
x=-12
2) 4^1-2x=64
4 - 2x =64
-2x = 64 - 4
-2x=60
x = 60:(-2)
x= -30
3) 2^1-x=8
2-x=8
-x= 8-2
-x= 6
x = -6

Answer 3

To solve these exponential equations, let's go step by step:

1. 2^(2 - x) = 16 We can rewrite 16 as 2^4 since 2^4 = 16. Now we have 2^(2 - x) = 2^4. Since the bases are the same, the exponents must be equal: 2 - x = 4. Solving for x: x = 2 - 4 = -2.

2. 4^(1 - 2x) = 64 We can rewrite 64 as 4^3 since 4^3 = 64. Now we have 4^(1 - 2x) = 4^3. Again, the bases are the same, so the exponents must be equal: 1 - 2x = 3. Solving for x: -2x = 3 - 1 = 2. x = 2 / -2 = -1.

3. 2^(1 - x) = 8 We can rewrite 8 as 2^3 since 2^3 = 8. Now we have 2^(1 - x) = 2^3. Again, the bases are the same, so the exponents must be equal: 1 - x = 3. Solving for x: -x = 3 - 1 = 2. x = -2.

Therefore, the solutions to the given equations are: x = -2, -1, -2.