Question

Знайдіть модуль вектора c =3a-2b, де a (1;-2), b(-1;3)

Answer 1

ОТВЕТ 13

Объяснение:

Answer 2

I can help you with your math problem. Here is the detailed solution:

First, we need to find the coordinates of the vector c by using the formula c = 3a - 2b. We substitute the values of a and b into the formula and get:

c = 3(1;-2) - 2(-1;3) = (3;-6) - (-2;6) = (5;-12)

Next, we need to find the modulus (or length) of the vector c by using the formula $$\|c\| = \sqrt{c_x^2 + c_y^2}$$, where $$c_x$$ and $$c_y$$ are the x and y components of c. We substitute the values of c into the formula and get:

$$\|c\| = \sqrt{5^2 + (-12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13$$

Therefore, the modulus of the vector c is 13.Ответь+подробно.++Знайдіть+модуль+вектора+c+=3a-2b,+де+a+(1;-2),+b(-1;3)+