Question

238 перевести в двоичную систему

Answer 1

Ответ:

..........

Объяснение:

.........................

Answer 2

Решение:

Разложим 238 на сумму чисел вида $2^{i}$:

$238 = 128 + 64 + 32 + 8 + 4 + 2 = 2^{7} + 2^{6} + 2^{5} + 2^{3} + 2^{2} + 2 = 11101110$

Ответ:

11101110

Answer 3

Converting 238 to Binary

To convert the decimal number 238 to binary, we can use the method of repeated division by 2. Here's how it works:

1. Divide 238 by 2: 238 ÷ 2 = 119, remainder 0. 2. Divide 119 by 2: 119 ÷ 2 = 59, remainder 1. 3. Divide 59 by 2: 59 ÷ 2 = 29, remainder 1. 4. Divide 29 by 2: 29 ÷ 2 = 14, remainder 1. 5. Divide 14 by 2: 14 ÷ 2 = 7, remainder 0. 6. Divide 7 by 2: 7 ÷ 2 = 3, remainder 1. 7. Divide 3 by 2: 3 ÷ 2 = 1, remainder 1. 8. Divide 1 by 2: 1 ÷ 2 = 0, remainder 1.

To obtain the binary representation, we read the remainders from bottom to top. In this case, the binary representation of 238 is 11101110.

Therefore, 238 in binary is 11101110.