Question

Помогите , пожалуйста с химией, 9 класс, цепочка... Be>BeO>BeSO4>K2[Be(OH)4] 1) Be+O2=BeO 2) BeO+H2So4=BeSo4+H2O 3) BeSo4+.....=K2[Be(OH)4] 4)BeO+KOH=K2BeO2+H2O 5)K2BeO+H2SO4=BeSO4+H2O 6)BeO+......=K2[Be(OH)4] 7)Be+.......=K2[Be(OH)4] На месте «....» надо поставить элемент, которого не хватает для решения хим.уравнения, и дополнить уравнения элементами и расставить коэффициенты. Заранее огромное спасибо!!

Answer 1

Chemical Equation Balancing

To balance the given chemical equation, we need to determine the missing element and complete the equation by adding the necessary elements and coefficients. Let's go step by step:

1. Be + O2 = BeO

This equation represents the reaction between beryllium (Be) and oxygen (O2) to form beryllium oxide (BeO). The equation is already balanced.

2. BeO + H2SO4 = BeSO4 + H2O

This equation represents the reaction between beryllium oxide (BeO) and sulfuric acid (H2SO4) to form beryllium sulfate (BeSO4) and water (H2O). The equation is already balanced.

3. BeSO4 + ... = K2[Be(OH)4]

To balance this equation, we need to determine the missing reactant and complete the equation. The missing reactant is potassium hydroxide (KOH). The balanced equation is:

   BeSO4 + 2KOH = K2[Be(OH)4] + K2SO4
   

4. BeO + KOH = K2BeO2 + H2O

This equation represents the reaction between beryllium oxide (BeO) and potassium hydroxide (KOH) to form potassium beryllate (K2BeO2) and water (H2O). The equation is already balanced.

5. K2BeO + H2SO4 = BeSO4 + H2O

This equation represents the reaction between potassium beryllate (K2BeO) and sulfuric acid (H2SO4) to form beryllium sulfate (BeSO4) and water (H2O). The equation is already balanced.

6. BeO + ... = K2[Be(OH)4]

To balance this equation, we need to determine the missing reactant and complete the equation. The missing reactant is water (H2O). The balanced equation is:

   BeO + 2H2O = K2[Be(OH)4]
   

7. Be + ... = K2[Be(OH)4]

To balance this equation, we need to determine the missing reactant and complete the equation. The missing reactant is water (H2O). The balanced equation is:

   Be + 2H2O = K2[Be(OH)4] + H2
   

So, the missing elements and the completed equations are as follows:

1. Be + O2 = BeO 2. BeO + H2SO4 = BeSO4 + H2O 3. BeSO4 + 2KOH = K2[Be(OH)4] + K2SO4 4. BeO + KOH = K2BeO2 + H2O 5. K2BeO + H2SO4 = BeSO4 + H2O 6. BeO + 2H2O = K2[Be(OH)4] 7. Be + 2H2O = K2[Be(OH)4] + H2

I hope this helps! Let me know if you have any further questions.