Question

Решите задачи по химии,срочно

Answer 1

1) 2С4H6 + 11O2 = 8CO2 + 6H2O
V(C4H6)  = 3л
n(C4H6) = 3/22.4 = 0,134 моль
n(O2) = 0,737 моль
V(O2) = 0,737 * 22,4 = 16,51 л

2)1. С2H4 + 3O2 = 2CO2 + 2H2O
    2. 2C3H6 + 9O2 = 6CO2 + 6H2O
    3. C4H8 + 6O2 = 4CO2 + 4H2O
V(сум) = 10л
w(C2H4) = 20%
w(C3H6) = 40%
w(C4H8) = 40%
V(O2) - ?
V(C2H4) = 10 * 0.2 = 2 л
V(C3H6) = 4л
V(C4H8) = 4л
M(C2H4) = 28г/м
M(C3H6) = 42 >>
M(C4H8) = 56 >>
n(C2H4) = 2/22.4 = 0.089
n(C3H8) = 4 / 22.4 = 0.18
n(C4H8) = 4 / 22.4 = 0.18
1. n(O2) = 3 * 0.089 = 0,267
2. n(O2) = 0.09 * 9 = 0.81
3. n(O2) = 0.18 * 6 = 1.08
1. V(O2) = 0,267 * 22.4 = 5,98
2. V(O2) = 0.81 * 22.4 = 18.15
3. V(O2) = 1.08 * 22.4 = 24.19