
Дописать реакцию и расставить коэффициенты методом электронного баланса. S + HNO3(разб) H2SO4 + ...


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Reaction and Balancing Coefficients using the Electronic Balance Method
To balance the given chemical equation using the electronic balance method, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
The given unbalanced equation is:
S + HNO3 (razb) + H2SO4 → ???
Let's balance the equation step by step:
Step 1: Balance the atoms other than hydrogen and oxygen.
The equation contains only one sulfur atom on the left side, so we need to balance it by placing a coefficient of 1 in front of H2SO4:
S + HNO3 (razb) + 1H2SO4 → ???
Step 2: Balance the hydrogen atoms.
The equation has 4 hydrogen atoms on the left side (2 in HNO3 and 2 in H2SO4). To balance the hydrogen atoms, we need to place a coefficient of 4 in front of HNO3:
S + 4HNO3 (razb) + 1H2SO4 → ???
Step 3: Balance the oxygen atoms.
The equation has 12 oxygen atoms on the right side (3 in HNO3 and 9 in H2SO4). To balance the oxygen atoms, we need to place a coefficient of 6 in front of HNO3:
S + 4HNO3 (razb) + 1H2SO4 → ???
Now, let's calculate the number of oxygen atoms on the left side:
- Sulfuric acid (H2SO4) has 4 oxygen atoms. - Nitric acid (HNO3) has 3 oxygen atoms.
So, the total number of oxygen atoms on the left side is 4 + (4 * 3) = 16.
To balance the oxygen atoms, we need to place a coefficient of 8 in front of H2SO4:
S + 4HNO3 (razb) + 8H2SO4 → ???
Now, let's calculate the number of sulfur atoms on the right side:
- Sulfuric acid (H2SO4) has 1 sulfur atom.
So, the total number of sulfur atoms on the right side is 8.
To balance the sulfur atoms, we need to place a coefficient of 8 in front of S:
8S + 4HNO3 (razb) + 8H2SO4 → ???
Finally, the balanced equation is:
8S + 4HNO3 (razb) + 8H2SO4 → ???
Please note that I was unable to find the complete balanced equation for the given reaction in the search results. If you have any additional information or context, I would be happy to assist you further.


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