Question

Электронная оболочка атома содержит 35 электронов. сколько протонов и нейтронов в ядре атома этого элемента 80Э ? определите элемент, напишите его электронную формулу. сколько неспаренных элементов содержится в атоме этого элемента в основном и возбужденном состояниях? ответ проиллюстрируйте.

Answer 1

Это же Бром - Br

1 неспаренный електрон
Br - 0
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5
Br - 1
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

Answer 2

Number of Protons and Neutrons in the Atom's Nucleus

To determine the number of protons and neutrons in the nucleus of an atom, we need to subtract the number of electrons from the atomic number. In this case, the atom has 35 electrons. Therefore, the number of protons is also 35, as the number of protons in an atom is equal to its atomic number.

To find the number of neutrons, we need to subtract the atomic number from the mass number. The mass number is the sum of protons and neutrons in the nucleus. The element in question is 80Э, but the mass number is not provided. Therefore, we cannot determine the exact number of neutrons without the mass number.

Element and Electron Configuration

The element with 35 electrons in its electronic shell is bromine (Br). The electron configuration of bromine is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^5.

Number of Unpaired Electrons in Ground and Excited States

To determine the number of unpaired electrons in the ground and excited states of bromine, we need to examine its electron configuration.

In the ground state, bromine has one unpaired electron in its 4p orbital. This can be represented as [Ar] 4s^2 3d^10 4p^1. Therefore, bromine has one unpaired electron in its ground state.

In the excited state, bromine can have different configurations depending on the specific excitation. Without further information about the excitation, it is not possible to determine the exact number of unpaired electrons in the excited state.

Please note that the number of unpaired electrons can change depending on the specific excitation of the atom.

I hope this helps! Let me know if you have any further questions.