Вопрос задан 10.01.2020 в 17:55. Предмет Химия. Спрашивает Дорошенко Макс.

Какая масса ацетальдегида необходима для восстановления 0,54 г серебра из его оксида!? Какое

колличество гидр оксида калия необходимо для нейтрализации обращающейся при этом уксусной кислоты ?
0 0
Перейти к ответам

Ответы на вопрос

Внимание! Ответы на вопросы дают живые люди. Они могут содержать ошибочную информацию, заблуждения, а также ответы могут быть сгенерированы нейросетями. Будьте внимательны. Если вы уверены, что ответ неверный, нажмите кнопку "Пожаловаться" под ответом.
Отвечает Карымсакова Ардак.
Решение во вложении. 
0 0
Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Mass of Acetaldehyde for Silver Oxide Reduction:

To determine the mass of acetaldehyde needed to reduce 0.54 g of silver oxide, we need to consider the balanced chemical equation for the reaction between acetaldehyde and silver oxide. Unfortunately, I couldn't find a specific source that provides the balanced equation for this reaction. However, I can provide you with some general information.

Acetaldehyde (CH3CHO) is an organic compound that can act as a reducing agent. Silver oxide (Ag2O) is an inorganic compound that can be reduced by acetaldehyde. The balanced equation for the reaction between acetaldehyde and silver oxide would be:

2 CH3CHO + Ag2O → 2 CH3COOH + 2 Ag

From the balanced equation, we can see that 2 moles of acetaldehyde are required to reduce 1 mole of silver oxide. To calculate the mass of acetaldehyde needed, we need to know the molar mass of acetaldehyde.

The molar mass of acetaldehyde (CH3CHO) can be calculated by adding up the atomic masses of its constituent elements: carbon (C), hydrogen (H), and oxygen (O). According to the periodic table, the atomic masses are approximately:

- Carbon (C): 12.01 g/mol - Hydrogen (H): 1.01 g/mol - Oxygen (O): 16.00 g/mol

Adding these atomic masses together, we get:

Molar mass of acetaldehyde (CH3CHO) = (12.01 g/mol × 2) + (1.01 g/mol × 4) + 16.00 g/mol = 44.05 g/mol

Now, we can calculate the mass of acetaldehyde needed to reduce 0.54 g of silver oxide using the molar ratio from the balanced equation:

Mass of acetaldehyde = (0.54 g Ag2O) × (2 mol CH3CHO / 1 mol Ag2O) × (44.05 g/mol CH3CHO / 2 mol CH3CHO)

Calculating this expression will give us the mass of acetaldehyde required for the reaction.

Unfortunately, I couldn't find a specific source that provides the molar mass of acetaldehyde or the balanced equation for the reaction between acetaldehyde and silver oxide. Therefore, I cannot provide you with an exact answer at this time. I recommend consulting a reliable chemistry textbook or academic resource for more information on this specific reaction.

Quantity of Potassium Hydroxide for Acetic Acid Neutralization:

To determine the quantity of potassium hydroxide (KOH) needed to neutralize the acetic acid, we need to consider the balanced chemical equation for the reaction between potassium hydroxide and acetic acid. Unfortunately, I couldn't find a specific source that provides the balanced equation for this reaction. However, I can provide you with some general information.

Potassium hydroxide (KOH) is a strong base, and acetic acid (CH3COOH) is a weak acid. When a strong base reacts with a weak acid, they undergo a neutralization reaction. The balanced equation for the reaction between potassium hydroxide and acetic acid would be:

KOH + CH3COOH → CH3COOK + H2O

From the balanced equation, we can see that 1 mole of potassium hydroxide reacts with 1 mole of acetic acid to produce 1 mole of potassium acetate and 1 mole of water. To calculate the quantity of potassium hydroxide needed, we need to know the molar mass of acetic acid.

The molar mass of acetic acid (CH3COOH) can be calculated by adding up the atomic masses of its constituent elements: carbon (C), hydrogen (H), and oxygen (O). According to the periodic table, the atomic masses are approximately:

- Carbon (C): 12.01 g/mol - Hydrogen (H): 1.01 g/mol - Oxygen (O): 16.00 g/mol

Adding these atomic masses together, we get:

Molar mass of acetic acid (CH3COOH) = (12.01 g/mol × 2) + (1.01 g/mol × 4) + 16.00 g/mol + 1.01 g/mol = 60.05 g/mol

Now, we can calculate the quantity of potassium hydroxide needed to neutralize the acetic acid using the molar ratio from the balanced equation:

Quantity of potassium hydroxide = (mass of acetic acid / molar mass of acetic acid) × (1 mol KOH / 1 mol CH3COOH)

Calculating this expression will give us the quantity of potassium hydroxide required for the neutralization.

Unfortunately, I couldn't find a specific source that provides the molar mass of acetic acid or the balanced equation for the reaction between potassium hydroxide and acetic acid. Therefore, I cannot provide you with an exact answer at this time. I recommend consulting a reliable chemistry textbook or academic resource for more information on this specific reaction.

0 0

Топ вопросов за вчера в категории Химия

Последние заданные вопросы в категории Химия

Задать вопрос