Question

Сколько молекул сульфида алюминия содержится в 86 г?

Answer 1

M = 86 (г)

M(Al2S3)=2*27+3*32=150 (г/моль)
n=m/M=86/150= 0.57 (моль)
N=Na*n, где Na - число Авогадро = 6.02*10^23 (молекул/моль)
N=6.02*10^23*0.57=3.4314*10^23 (молекул)

Answer 2

Calculating the number of moles of aluminum sulfide

To calculate the number of moles of aluminum sulfide (Al2S3) in 86 g, we use the molar mass:

The molar mass of Al2S3 is 144.1 g/mol To calculate the number of moles, we use the formula:

Moles = Mass / Molar Mass

Plugging in the values: **Moles of Al2S3 = Mass / Molar Mass = 86 g / 144.1 g/mol = 0.597 mol**

So the number of moles of aluminum sulfide (Al2S3) contained in 86 g is 0.597 mol.