Question

Расставить коэффициенты с помощью электронного баланса HNO3→NO2+O2+H2O Помогите пожалуйста,дам 25 балов И если можете,то установите окисление с восстановлением,окислитель с восстановителем

Answer 1

4HNO3- 4NO2+2H2O+O2
N переходит из степени окисления +5 в N со степенью окисления +4 соответственно процесс будет называться восстановление а азот будет окислителем,кислород переходит из -2 в кислород со степенью окисления 0 соответственно процесс будет окислением а кислород восстановителем.
Электронный баланс
N+5 в N+4 +1 e Находим наименьшее общее кратное то есть 4. 4/1 это 4 а 4/4
O-2 в O 0. -4e это 1.коэффициэнты я расставил.

Answer 2

Balancing the Equation: HNO3 → NO2 + O2 + H2O

To balance the chemical equation HNO3 → NO2 + O2 + H2O, we need to ensure that the number of atoms of each element is the same on both sides of the equation. We can use an electronic balance method to determine the coefficients for each compound.

Let's go through the steps to balance the equation:

1. Start by counting the number of atoms for each element on both sides of the equation: - HNO3: 1 hydrogen (H), 1 nitrogen (N), and 3 oxygen (O) atoms - NO2: 1 nitrogen (N) and 2 oxygen (O) atoms - O2: 2 oxygen (O) atoms - H2O: 2 hydrogen (H) and 1 oxygen (O) atom

2. Begin by balancing the elements that appear in the fewest compounds. In this case, we can start with nitrogen (N): - There is 1 nitrogen (N) atom on the left side and 1 nitrogen (N) atom on the right side, so nitrogen is already balanced.

3. Next, balance the oxygen (O) atoms: - There are 3 oxygen (O) atoms in HNO3 and 2 oxygen (O) atoms in NO2, making a total of 5 oxygen (O) atoms on the left side. - On the right side, there are 2 oxygen (O) atoms in O2 and 1 oxygen (O) atom in H2O, making a total of 3 oxygen (O) atoms. - To balance the oxygen (O) atoms, we need to add a coefficient of 2 in front of HNO3 and a coefficient of 3 in front of NO2: 2HNO3 → 3NO2 + O2 + H2O

4. Finally, balance the hydrogen (H) atoms: - There is 2 hydrogen (H) atoms in H2O on the right side. - To balance the hydrogen (H) atoms, we need to add a coefficient of 4 in front of H2O: 2HNO3 → 3NO2 + O2 + 4H2O

Therefore, the balanced equation is: 2HNO3 → 3NO2 + O2 + 4H2O

Oxidation and Reduction in the Reaction

In the given reaction, HNO3 → NO2 + O2 + H2O, we can identify the oxidation and reduction processes by examining the changes in oxidation states of the elements involved.

- Oxidation: The oxidation state of an element increases in a reaction. In this case, the nitrogen (N) in HNO3 has an oxidation state of +5, and in NO2, it has an oxidation state of +4. Therefore, nitrogen (N) is undergoing reduction.

- Reduction: The reduction state of an element decreases in a reaction. In this case, the oxygen (O) in HNO3 has an oxidation state of -2, and in O2, it has an oxidation state of 0. Therefore, oxygen (O) is undergoing oxidation.

Hence, in the reaction HNO3 → NO2 + O2 + H2O, nitrogen (N) is being reduced, and oxygen (O) is being oxidized.

I hope this helps! Let me know if you have any further questions.