Question

Какая масса хлорида натрия образуется при нейтрализации 16 г гидроксида натрия избытком соляной кислоты?

Answer 1

NaOH+HCl=NaCl+H2O
n=m/M(Mr)  M=Mr      Me(NaOh)=40  M=40г/моль
n(NaOH)=16/4-=0,4 моль
n(NaOH)=n(NaCl)  n(NaCL)= 0,4моль, по условию реакции
m= n*M)Mr)  Mr(NaCl)=56,5    М=56,5г/моль
m(NaCl)= 0,4*56,5=22,6г
Ответ:22,6г

Answer 2

N=16:40=0.4моль NaOH=NaCL
NaOH+HCL=NaCL+H2O
1-----------------1
m=M(NaCL)*n=58.5*0.4=23.4г

Answer 3

Calculation of the Mass of Sodium Chloride Formed

To determine the mass of sodium chloride formed during the neutralization of 16 g of sodium hydroxide with an excess of hydrochloric acid, we need to consider the balanced chemical equation for the reaction:

NaOH + HCl -> NaCl + H2O

From the equation, we can see that one mole of sodium hydroxide reacts with one mole of hydrochloric acid to produce one mole of sodium chloride and one mole of water.

To calculate the mass of sodium chloride formed, we need to convert the given mass of sodium hydroxide to moles, and then use the mole ratio from the balanced equation to determine the moles of sodium chloride formed. Finally, we can convert the moles of sodium chloride to grams.

Step 1: Convert Sodium Hydroxide to Moles

The molar mass of sodium hydroxide (NaOH) is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H). From the periodic table, we find:

- Atomic mass of Na = 22.99 g/mol - Atomic mass of O = 16.00 g/mol - Atomic mass of H = 1.01 g/mol

Adding these values together, we get:

- Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

To convert the mass of sodium hydroxide to moles, we divide the given mass by the molar mass:

- Moles of NaOH = 16 g / 40.00 g/mol = 0.40 mol

Step 2: Determine Moles of Sodium Chloride

From the balanced equation, we know that the mole ratio between sodium hydroxide and sodium chloride is 1:1. Therefore, the moles of sodium chloride formed will also be 0.40 mol.

Step 3: Convert Moles of Sodium Chloride to Grams

To convert moles of sodium chloride to grams, we multiply the moles by the molar mass of sodium chloride (NaCl). The molar mass of sodium chloride is the sum of the atomic masses of sodium (Na) and chlorine (Cl):

- Atomic mass of Na = 22.99 g/mol - Atomic mass of Cl = 35.45 g/mol

Adding these values together, we get:

- Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Multiplying the moles of sodium chloride by the molar mass, we get:

- Mass of NaCl = 0.40 mol * 58.44 g/mol = 23.38 g

Therefore, the mass of sodium chloride formed during the neutralization of 16 g of sodium hydroxide with an excess of hydrochloric acid is approximately 23.38 grams.