Question

Проведите реакцию ионного обменаииежду растворами хлорида бария и сульфата натрия НУР в молекульном полном и сокращенном ионном виде

Answer 1

BaCl₂ + Na₂SO₄ = BaSO₄ + 2NaCl
Ba²⁺ + 2Cl⁻ + 2Na⁺ + SO₄²⁻ = BaSO₄ + 2Na⁺ + 2Cl⁻
Ba²⁺ + SO₄²⁻ = BaSO₄

Answer 2

Reaction between Barium Chloride and Sodium Sulfate

The reaction between barium chloride (BaCl2) and sodium sulfate (Na2SO4) is a classic example of an ion exchange reaction. In this reaction, the cations and anions in the reactants switch partners to form new compounds.

The balanced chemical equation for the reaction is as follows:

BaCl2 + Na2SO4 → BaSO4 + 2NaCl

In the molecular form, the reaction can be represented as:

Barium Chloride + Sodium Sulfate → Barium Sulfate + Sodium Chloride

Now, let's break down the reaction in both the molecular and ionic forms.

Molecular Form:

In the molecular form, the reactants and products are represented as complete molecules. The reaction between barium chloride and sodium sulfate in the molecular form can be written as:

BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaCl(aq)

In this form, the reactants are dissolved in water (indicated by "(aq)" for aqueous) and the products are either solid (indicated by "(s)") or dissolved in water as well.

Ionic Form:

In the ionic form, the reactants and products are represented as individual ions. The reaction between barium chloride and sodium sulfate in the ionic form can be written as:

Ba^2+(aq) + 2Cl^-(aq) + 2Na^+(aq) + SO4^2-(aq) → BaSO4(s) + 2Na^+(aq) + 2Cl^-(aq)

In this form, the reactants and products are shown as their respective ions. The barium ion (Ba^2+) and sulfate ion (SO4^2-) combine to form barium sulfate (BaSO4), which is insoluble and precipitates out of the solution as a solid. The sodium ions (Na^+) and chloride ions (Cl^-) remain in the solution as they were before the reaction.

It is important to note that the reaction between barium chloride and sodium sulfate is a double displacement reaction, where the cations and anions in the reactants exchange partners to form new compounds. The formation of the insoluble barium sulfate is a driving force for the reaction.

I hope this explanation helps! Let me know if you have any further questions.