Question

Cuso4+ Bacl - Na2co3+ KOH -

Answer 1

СuSO4+BaCl2=CuCl2+BaSO4             Na2CO3+2KOH=K2CO3+2NAOH

Answer 2

Cuso4+ 2Bacl2=CuCl2+BSO4

Na2co3+2 KOH=>K2CO3+2NaOH

Answer 3

Reaction between CuSO4, BaCl2, Na2CO3, and KOH

The reaction between CuSO4 (copper(II) sulfate), BaCl2 (barium chloride), Na2CO3 (sodium carbonate), and KOH (potassium hydroxide) can be described as follows:

CuSO4 + BaCl2 + Na2CO3 + 2KOH → Cu(OH)2 + BaCO3 + 2NaCl + K2SO4

In this reaction, copper(II) sulfate reacts with barium chloride, sodium carbonate, and potassium hydroxide to form copper(II) hydroxide, barium carbonate, sodium chloride, and potassium sulfate.

Please note that the balanced equation provided above is a general representation of the reaction. The actual reaction conditions, such as temperature and concentration, may affect the outcome of the reaction.