Question

При нагревании метана (CH4) объемом 4,48 л (н.у.) без доступа воздуха образовалось 2г сажи (углерод). Расчитайте выход продукта по сравнению с теоритически вычисленным. Решите пропорцией, пожалуйста)

Answer 1

СН4 --> С + 2Н2 
22,4 -------12 
4,48 ------х 
х = 2,4 г (теор. выход) 
2,4 ---100% 
2 ------х 
х = 83,3%

Answer 2

Calculation of the Theoretical Yield of Carbon (Soot) from Methane (CH4)

To calculate the theoretical yield of carbon (soot) from methane (CH4), we need to use the balanced chemical equation for the combustion of methane:

CH4 + 2O2 -> CO2 + 2H2O

According to the equation, 1 mole of methane (CH4) reacts with 2 moles of oxygen (O2) to produce 1 mole of carbon dioxide (CO2) and 2 moles of water (H2O).

Given that the initial volume of methane is 4.48 L at standard temperature and pressure (STP) and that 2 grams of carbon (soot) is formed, we can calculate the moles of methane used and the moles of carbon produced.

1. Calculate the moles of methane used: - The molar mass of methane (CH4) is 16.04 g/mol (12.01 g/mol for carbon + 4 * 1.01 g/mol for hydrogen). - Moles of methane = mass of methane / molar mass of methane = 2 g / 16.04 g/mol = 0.1246 mol

2. Calculate the moles of carbon produced: - From the balanced chemical equation, we know that 1 mole of methane produces 1 mole of carbon dioxide. - Therefore, the moles of carbon produced will be equal to the moles of methane used. - Moles of carbon = 0.1246 mol

3. Calculate the theoretical yield of carbon (soot): - The molar mass of carbon (soot) is 12.01 g/mol. - Theoretical yield of carbon = moles of carbon * molar mass of carbon = 0.1246 mol * 12.01 g/mol = 1.495 g

Therefore, the theoretical yield of carbon (soot) from the given amount of methane is approximately 1.495 grams.

Please note that this calculation assumes complete combustion of methane and does not take into account any other possible reactions or side reactions that may occur.