Question

А)cacl2+zn= cu+ zncl2 В) h2s+o2=s+h2oРасмотреть как овр очень срочно

Answer 1

А) Cu(+2)+2e=Cu(0) - окислитель
Zn(0)-2e=Zn(+2) - восстановитель
Б) S(-2)-2e=S(0) - восстановитель
O2(0)+4e=2O(-2) - окислитель

Answer 2

A) cacl2 + zn = cu + zncl2

The given chemical equation represents a reaction between calcium chloride (CaCl2) and zinc (Zn), resulting in the formation of copper (Cu) and zinc chloride (ZnCl2). Let's break down the equation and understand the reaction:

CaCl2 + Zn -> Cu + ZnCl2

In this reaction, calcium chloride (CaCl2) reacts with zinc (Zn) to produce copper (Cu) and zinc chloride (ZnCl2). This is a redox reaction, where oxidation and reduction occur simultaneously.

The oxidation half-reaction involves the loss of electrons, and in this case, zinc (Zn) is oxidized to zinc ions (Zn2+):

Zn -> Zn2+ + 2e-

The reduction half-reaction involves the gain of electrons, and in this case, copper ions (Cu2+) are reduced to copper (Cu):

Cu2+ + 2e- -> Cu

By combining the two half-reactions, we get the overall balanced equation:

CaCl2 + Zn -> Cu + ZnCl2

Please note that the equation should be balanced to ensure that the number of atoms of each element is the same on both sides of the equation. However, without the coefficients provided, it is not possible to balance the equation accurately.

B) h2s + o2 = s + h2o

The given chemical equation represents a reaction between hydrogen sulfide (H2S) and oxygen (O2), resulting in the formation of sulfur (S) and water (H2O). Let's break down the equation and understand the reaction:

H2S + O2 -> S + H2O

In this reaction, hydrogen sulfide (H2S) reacts with oxygen (O2) to produce sulfur (S) and water (H2O). This is a combustion reaction, where a substance reacts with oxygen to produce heat and light.

The balanced equation for this reaction is:

2H2S + 3O2 -> 2S + 2H2O

Please note that the equation has been balanced to ensure that the number of atoms of each element is the same on both sides of the equation. The coefficients in front of each compound indicate the number of molecules or moles involved in the reaction.

If you have any further questions or need additional information, feel free to ask!