Question

1.alcl3--->al(oh)3---->al2(so4)3 2.al(oh)3--->naalo2

Answer 1

AlCl3+3NaOh=3NaCl+Al(OH)3
2Al(OH)3+3H2SO4=6H2O+Al2(SO4)3
Al(OH)3+NaOH=(сплавление)=NaAlO2+H2O

Answer 2

1. The chemical reaction you provided is a series of reactions involving aluminum chloride (AlCl3) and aluminum hydroxide (Al(OH)3) that result in the formation of aluminum sulfate (Al2(SO4)3) and sodium aluminate (NaAlO2).

The first reaction is the conversion of aluminum chloride to aluminum hydroxide: AlCl3 → Al(OH)3.

The second reaction involves the conversion of aluminum hydroxide to sodium aluminate: Al(OH)3 → NaAlO2.

2. Let's break down each reaction and explain the steps involved:

a. Conversion of aluminum chloride to aluminum hydroxide: - Aluminum chloride (AlCl3) reacts with water (H2O) to form aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl): AlCl3 + 3H2O → Al(OH)3 + 3HCl.

b. Conversion of aluminum hydroxide to sodium aluminate: - Aluminum hydroxide (Al(OH)3) reacts with sodium hydroxide (NaOH) to form sodium aluminate (NaAlO2) and water (H2O): Al(OH)3 + NaOH → NaAlO2 + 2H2O.

3. It's important to note that these reactions are simplified representations and may not capture all the details and conditions required for the reactions to occur. The actual reaction conditions, such as temperature, pressure, and catalysts, may vary depending on the specific experimental setup.

4. If you need more information or have any further questions, feel free to ask!