Question

Очень срочно!!! При взаимодействии 11,4л аммиака с соляной кислотой получили 20 г NH4CL вычислите массовую долю выхода продукта реакции. Пожалуйста!!!

Answer 1

Для начала мы вычилсим теоретический выход , из 11.4 литра аммиака, мы получили 27.22 грамм.
А по условии нам дали ,что мы получили 20 гр.
Найдем выход продукта , практический делим на теоретический , и умножим на 100%.

Answer 2

Calculation of the Mass Fraction of the Reaction Product

To calculate the mass fraction of the reaction product, we need to determine the amount of NH4Cl produced and compare it to the initial amount of NH3 used.

Given: - Volume of ammonia (NH3) used: 11.4 L - Mass of NH4Cl produced: 20 g

To calculate the mass fraction, we can use the formula:

Mass fraction = (mass of NH4Cl produced / initial mass of NH3) * 100%

However, we need to convert the volume of NH3 to its corresponding mass using its molar mass.

The molar mass of NH3 is 17.03 g/mol.

Calculation Steps:

Step 1: Convert the volume of NH3 to mass using its molar mass. - Molar mass of NH3 = 17.03 g/mol - Volume of NH3 = 11.4 L

To convert the volume of NH3 to mass, we need to use the ideal gas law equation:

PV = nRT

Where: - P is the pressure (assumed constant) - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature (assumed constant)

Since the pressure, temperature, and volume are constant, we can simplify the equation to:

n = (PV) / RT

Assuming standard temperature and pressure (STP), which is 0°C (273.15 K) and 1 atm, respectively, we can calculate the number of moles of NH3:

n = (1 atm * 11.4 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

Step 2: Calculate the initial mass of NH3. - Number of moles of NH3 = calculated in Step 1 - Molar mass of NH3 = 17.03 g/mol

Initial mass of NH3 = (number of moles of NH3) * (molar mass of NH3)

Step 3: Calculate the mass fraction of NH4Cl. - Mass of NH4Cl produced = 20 g (given) - Initial mass of NH3 = calculated in Step 2

Mass fraction = (mass of NH4Cl produced / initial mass of NH3) * 100%

Now, let's calculate the mass fraction of the reaction product.

Calculation:

Step 1: Convert the volume of NH3 to mass: - P = 1 atm - V = 11.4 L - R = 0.0821 L·atm/(mol·K) - T = 273.15 K

n = (1 atm * 11.4 L) / (0.0821 L·atm/(mol·K) * 273.15 K) = 0.500 mol

Step 2: Calculate the initial mass of NH3: - Number of moles of NH3 = 0.500 mol - Molar mass of NH3 = 17.03 g/mol

Initial mass of NH3 = (0.500 mol) * (17.03 g/mol) = 8.515 g

Step 3: Calculate the mass fraction of NH4Cl: - Mass of NH4Cl produced = 20 g - Initial mass of NH3 = 8.515 g

Mass fraction = (20 g / 8.515 g) * 100% = 235.0%

The mass fraction of the reaction product, NH4Cl, is 235.0%.

Please note that the calculated mass fraction is greater than 100%, which suggests a calculation error or a mistake in the given information. It is important to double-check the values and calculations to ensure accuracy.