Question

Вычислить количество вещества и массу оксида меди, который может прореагировать с азотной кислотой с массой 12,6 грамм

Answer 1

CuO+2HNO3=Cu(NO3)2+H2O
n=m/M(Mr)  M=Mr  Mr(HNO3)=63  M=63г/моль
n(HNO3)=12,3/63=0,29(моль)
n(HNO3)/n(CuO)=2/1, след.,
 n(CuO)=0,29/2=0,145(моль)
m=n*M(Mr)  M=Mr  Mr(CuO)=80   m=80г/моль
m(CuO)=0,145*80=11,6(г)
 Ответ: 11,6г, 0,145 моль

Answer 2

Calculating the Amount of Substance and Mass of Copper Oxide

To calculate the amount of substance and mass of copper oxide that can react with nitric acid, we need to use the balanced chemical equation for the reaction between copper oxide (CuO) and nitric acid (HNO3).

The balanced chemical equation for the reaction is as follows:

CuO + 2HNO3 → Cu(NO3)2 + H2O

According to the equation, one mole of copper oxide reacts with two moles of nitric acid to produce one mole of copper nitrate and one mole of water.

To calculate the amount of substance of copper oxide, we can use the molar mass of copper oxide, which is 79.55 g/mol

The molar mass of nitric acid is 63.01 g/mol

Given that the mass of nitric acid is 12.6 grams, we can calculate the amount of substance of nitric acid using the formula:

Amount of substance (in moles) = Mass (in grams) / Molar mass (in g/mol)

Let's calculate the amount of substance of nitric acid:

Amount of substance of nitric acid = 12.6 g / 63.01 g/mol = 0.2 mol

Since the balanced chemical equation shows that one mole of copper oxide reacts with two moles of nitric acid, the amount of substance of copper oxide will be half of the amount of substance of nitric acid.

Amount of substance of copper oxide = 0.2 mol / 2 = 0.1 mol

To calculate the mass of copper oxide, we can use the formula:

Mass (in grams) = Amount of substance (in moles) × Molar mass (in g/mol)

Let's calculate the mass of copper oxide:

Mass of copper oxide = 0.1 mol × 79.55 g/mol = 7.955 grams

Therefore, the amount of substance of copper oxide that can react with 12.6 grams of nitric acid is 0.1 mol, and the mass of copper oxide is 7.955 grams.

Please note that the molar mass values and the balanced chemical equation used in this calculation are based on general chemistry principles. The actual values may vary depending on the specific isotopes and conditions involved in the reaction.