Вопрос задан 08.05.2019 в 13:33. Предмет Химия. Спрашивает Миллер Марк.

Доберiть коефiцiэнт до запропонованих схем хiмiчних реакцiй: 1. Na+H2=NaH 2.Al+Cl2=AlCl3

3.P+O2=P2O5 4.KClO3=KCl+O2
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Отвечает Куангалиева Раушан.
2Na + H2 -> 2NaH
2Al + 3Cl2 -> 2AlCl3
4P + 5O2 -> 2P2O5
2KClO3 -> 2KCl + 3O2
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Отвечает Долинская Екатерина.
1. 2Na + H2 = 2NaH
2. 2Al + 3Cl2 = 2AlCl3
3. 4P + 5O2 = 2P2O5
4. 2KClO3 = 2KCl + 3O2
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance each equation one by one:

1. Na + H2 = NaH

To balance this equation, we need to ensure that the number of sodium (Na) atoms and hydrogen (H) atoms is the same on both sides.

On the left side, we have one sodium atom (Na) and two hydrogen atoms (H2). On the right side, we have one sodium atom (Na) and one hydrogen atom (H).

To balance the equation, we can multiply the hydrogen (H) on the right side by 2:

Na + H2 = NaH

2H2 + Na = 2NaH

Now, the equation is balanced with one sodium atom (Na) and four hydrogen atoms (2H2) on both sides.

2. Al + Cl2 = AlCl3

To balance this equation, we need to ensure that the number of aluminum (Al) atoms and chlorine (Cl) atoms is the same on both sides.

On the left side, we have one aluminum atom (Al) and two chlorine atoms (Cl2). On the right side, we have one aluminum atom (Al) and three chlorine atoms (Cl3).

To balance the equation, we can multiply the chlorine (Cl2) on the left side by 3:

3Cl2 + Al = AlCl3

Now, the equation is balanced with one aluminum atom (Al) and six chlorine atoms (3Cl2) on both sides.

3. P + O2 = P2O5

To balance this equation, we need to ensure that the number of phosphorus (P) atoms and oxygen (O) atoms is the same on both sides.

On the left side, we have one phosphorus atom (P) and two oxygen atoms (O2). On the right side, we have two phosphorus atoms (P2) and five oxygen atoms (O5).

To balance the equation, we can multiply the phosphorus (P) on the left side by 2 and the oxygen (O2) on the left side by 5:

4P + 5O2 = P2O5

Now, the equation is balanced with four phosphorus atoms (4P) and ten oxygen atoms (5O2) on both sides.

4. KClO3 = KCl + O2

To balance this equation, we need to ensure that the number of potassium (K) atoms, chlorine (Cl) atoms, and oxygen (O) atoms is the same on both sides.

On the left side, we have one potassium atom (K), one chlorine atom (Cl), and three oxygen atoms (O3). On the right side, we have one potassium atom (K), one chlorine atom (Cl), and two oxygen atoms (O2).

To balance the equation, we can leave the potassium (K) and chlorine (Cl) as they are and multiply the oxygen (O3) on the left side by 2:

KClO3 = KCl + 2O2

Now, the equation is balanced with one potassium atom (K), one chlorine atom (Cl), and four oxygen atoms (2O2) on both sides.

Summary

The balanced chemical equations are:

1. Na + 2H2 = 2NaH 2. 3Cl2 + Al = AlCl3 3. 4P + 5O2 = P2O5 4. KClO3 = KCl + 2O2

Please note that these balanced equations represent the conservation of atoms in a chemical reaction.

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