Question

1)2CH3COOH+2Mg=2(CH3(COO)2Mg+H2 2)CH3COOH Na2CO3=CH3COONa H2CO3 3)CH3COONa+H2SO4=CH3COOH+Na2SO4 йонна повна і скорочена форма реакції

Answer 1

2CH3COOH + Mg = (CH3COO)2Mg + H2Mg(0) + 2H(+) = Mg(2+) + H2
2CH3COO(-) + 2H(+) +2Na(+) + CO3(2-) = 2CH3COO(-) + 2Na(+) + H2O+CO22H(+) + CO3(2-) = H2O+CO2
2CH3COO(-) + 2Na(+) + 2H(+) + SO4(2-) = 2CH3COOH + 2Na(+) + SO4(2-)2CH3COO(-) + 2H(+) = CH3COOH

Answer 2

2CH3COOH + Mg = (CH3COO)2Mg + H2
Mg(0) + 2H(+) = Mg(2+) + H2

2CH3COO(-) + 2H(+) +2Na(+) + CO3(2-) = 2CH3COO(-) + 2Na(+) + H2O+CO2
2H(+) + CO3(2-) = H2O+CO2

2CH3COO(-) + 2Na(+) + 2H(+) + SO4(2-) = 2CH3COOH + 2Na(+) + SO4(2-)
2CH3COO(-) + 2H(+) = CH3COOH

Answer 3

1) The reaction between 2CH3COOH and 2Mg produces 2(CH3(COO)2Mg and H2 gas. - The balanced equation for this reaction is: 2CH3COOH + 2Mg -> 2(CH3(COO)2Mg + H2. - The reaction involves the reaction of two molecules of acetic acid (CH3COOH) with two atoms of magnesium (Mg), resulting in the formation of two molecules of magnesium acetate (CH3(COO)2Mg) and the release of hydrogen gas (H2) [[1]].

2) The reaction between CH3COOH and Na2CO3 produces CH3COONa and H2CO3. - The balanced equation for this reaction is: CH3COOH + Na2CO3 -> CH3COONa + H2CO3. - In this reaction, acetic acid (CH3COOH) reacts with sodium carbonate (Na2CO3) to form sodium acetate (CH3COONa) and carbonic acid (H2CO3) [[2]].

3) The reaction between CH3COONa and H2SO4 produces CH3COOH and Na2SO4. - The balanced equation for this reaction is: CH3COONa + H2SO4 -> CH3COOH + Na2SO4. - In this reaction, sodium acetate (CH3COONa) reacts with sulfuric acid (H2SO4) to form acetic acid (CH3COOH) and sodium sulfate (Na2SO4) [[3]].

Ionic and Complete Molecular Equation: - The ionic equation for the reaction between CH3COONa and H2SO4 is: CH3COONa + H2SO4 -> CH3COOH + Na2SO4. - The complete molecular equation for the reaction is the same as the balanced equation mentioned above.

I hope this helps! Let me know if you have any further questions.