Question

К смеси массой 8г, состоящей из меди и оксида меди(II), добавили избыток соляной кислоты. В результате реакции образовался хлорид меди(II) массой 5,4г. Определите массовую долю (в процентах) оксида меди(II) в исходной смеси. Ответ округлите до целого числа.

Answer 1

HCI+Cu=на реакцию не пойдёт

8гр хгр
Cu0+2HCl=CuCl2+H20
80гр 135гр
8×135÷80=13.5
13.5гр------100%
5.4гр-------Х%
5.4×100÷13.5=40

0:оксиде медь(2) в процентах 40%

Answer 2

Task: Determine the mass percentage of copper(II) oxide in the initial mixture.

To determine the mass percentage of copper(II) oxide in the initial mixture, we need to calculate the mass of copper(II) oxide and the mass of the entire mixture.

Let's denote the mass of the copper(II) oxide as m(CuO) and the mass of the entire mixture as m(total).

According to the information provided, the mass of the copper(II) chloride formed is 5.4g.

We can use the equation of the reaction to determine the molar ratio between copper(II) chloride and copper(II) oxide:

CuO + 2HCl → CuCl2 + H2O

From the equation, we can see that 1 mole of copper(II) oxide reacts with 2 moles of hydrochloric acid to form 1 mole of copper(II) chloride.

Using the molar mass of copper(II) chloride (CuCl2) and copper(II) oxide (CuO), we can calculate the number of moles of copper(II) chloride formed:

n(CuCl2) = m(CuCl2) / M(CuCl2)

where n(CuCl2) is the number of moles of copper(II) chloride, m(CuCl2) is the mass of copper(II) chloride formed, and M(CuCl2) is the molar mass of copper(II) chloride.

Similarly, we can calculate the number of moles of copper(II) oxide reacted:

n(CuO) = n(CuCl2) / 1

Since the molar ratio between copper(II) oxide and copper(II) chloride is 1:1.

Finally, we can calculate the mass of copper(II) oxide:

m(CuO) = n(CuO) * M(CuO)

where M(CuO) is the molar mass of copper(II) oxide.

To determine the mass percentage of copper(II) oxide in the initial mixture, we can use the following formula:

Mass percentage of CuO = (m(CuO) / m(total)) * 100%

Let's calculate the mass percentage of copper(II) oxide in the initial mixture.

Calculation:

Given: - Mass of copper(II) chloride formed (m(CuCl2)) = 5.4g

Using the molar masses: - Molar mass of copper(II) chloride (CuCl2) =- Molar mass of copper(II) oxide (CuO) = Using the equations mentioned above, we can calculate the mass of copper(II) oxide (m(CuO)):

n(CuCl2) = m(CuCl2) / M(CuCl2) n(CuO) = n(CuCl2) / 1 m(CuO) = n(CuO) * M(CuO)

Finally, we can calculate the mass percentage of copper(II) oxide:

Mass percentage of CuO = (m(CuO) / m(total)) * 100%

Let's perform the calculations.