Question

Вычисли, какая масса гидроксида никеля(II) выпадет в осадок при взаимодействии раствора сульфатаникеля(II) с раствором, содержащим 0,02моль гидроксида натрия.

Answer 1

Я конечно не уверена, но может так?

Answer 2

Calculating the Mass of Nickel(II) Hydroxide Precipitate

To calculate the mass of nickel(II) hydroxide that will precipitate when a solution of nickel(II) sulfate reacts with a solution containing 0.02 moles of sodium hydroxide, we can use the following steps:

1. Balanced Chemical Equation: - First, we need to write the balanced chemical equation for the reaction between nickel(II) sulfate and sodium hydroxide to determine the stoichiometry of the reaction.

2. Molar Ratio: - Once we have the balanced chemical equation, we can use the stoichiometry to determine the molar ratio between nickel(II) sulfate and sodium hydroxide.

3. Calculating the Mass: - Finally, we can use the molar ratio to calculate the mass of nickel(II) hydroxide that will precipitate.

Balanced Chemical Equation:

The balanced chemical equation for the reaction between nickel(II) sulfate and sodium hydroxide is:

``` NiSO4 + 2NaOH → Ni(OH)2 + Na2SO4 ``` .

Molar Ratio:

From the balanced chemical equation, we can see that 1 mole of nickel(II) sulfate reacts with 2 moles of sodium hydroxide to produce 1 mole of nickel(II) hydroxide.

Calculating the Mass:

Given that the solution contains 0.02 moles of sodium hydroxide, we can use the molar ratio to calculate the mass of nickel(II) hydroxide that will precipitate.

The molar mass of nickel(II) hydroxide (Ni(OH)2) is approximately 92.71 g/mol.

Using the molar ratio and the given moles of sodium hydroxide, we can calculate the mass of nickel(II) hydroxide that will precipitate:

0.02 moles of NaOH * (1 mole of Ni(OH)2 / 2 moles of NaOH) * (92.71 g/mol) = X grams

Solving for X, we find that the mass of nickel(II) hydroxide that will precipitate is approximately 0.9271 grams.

Therefore, when the solution containing 0.02 moles of sodium hydroxide reacts with nickel(II) sulfate, approximately 0.9271 grams of nickel(II) hydroxide will precipitate.