Question

Определите количество газа , занимающего при нормальных условиях объем 5,6 л

Answer 1

Это 11/44=0,25 моль. Значит 22,4*0,25=5,6 литра

Answer 2

Calculating Gas Volume at Normal Conditions

To determine the volume of gas at normal conditions, we can use the ideal gas law, which states that PV = nRT, where: - P = pressure - V = volume - n = number of moles of gas - R = ideal gas constant - T = temperature in Kelvin

Given: - Volume (V) = 5.6 L - Normal conditions: pressure (P) = 1 atm, temperature (T) = 273 K

We can rearrange the ideal gas law to solve for the number of moles of gas (n): n = (PV) / RT

Substitute the given values: n = (1 atm * 5.6 L) / (0.0821 L*atm/mol*K * 273 K)

Calculating the Number of Moles: n = (1 * 5.6) / (0.0821 * 273) = 0.227 moles of gas

Therefore, the gas occupying a volume of 5.6 L at normal conditions contains approximately 0.227 moles of gas.