Question

Які з наведених оксидів взаємодіють із водою:барій оксид,калій оксид,купрум(2) оксид,силіцій(4) оксид,цинк оксид,сульфур(6) оксид?напишіь рівняння реакцій

Answer 1

BaO + H2O -> Ba(OH)2
K2O + H2O -> 2KOH
SO3 + H2O -> H2SO4

Answer 2

Interaction of Oxides with Water and Balanced Chemical Equations

Barium Oxide: When barium oxide reacts with water, it forms barium hydroxide. The balanced chemical equation for the reaction is: ``` BaO + H2O → Ba(OH)2 ```

Potassium Oxide: Potassium oxide reacts with water to produce potassium hydroxide. The balanced chemical equation for the reaction is: ``` K2O + H2O → 2KOH ```

Copper(II) Oxide: Copper(II) oxide reacts with water to yield copper(II) hydroxide. The balanced chemical equation for the reaction is: ``` CuO + H2O → Cu(OH)2 ```

Silicon(IV) Oxide: Silicon(IV) oxide does not react with water under normal conditions. No balanced chemical equation is available as there is no reaction.

Zinc Oxide: Zinc oxide reacts with water to form zinc hydroxide. The balanced chemical equation for the reaction is: ``` ZnO + H2O → Zn(OH)2 ```

Sulfur(IV) Oxide (Sulfur Dioxide): Sulfur(IV) oxide reacts with water to produce sulfurous acid. The balanced chemical equation for the reaction is: ``` SO2 + H2O → H2SO3 ```

I hope this information is helpful! If you have further questions or need additional assistance, feel free to ask.