Question

C какими из перечисленных веществ вступит в реакцию оксид серы(IV): алюминий, вода, гидроксид натрия, хлорид калия, оксид хлора(VII), оксид бария? Составьте уравнения реакций.

Answer 1

4NaOH+3Ca=3CaO+Na2O++2Na+2H2
SO3 + 2NaOH = Na2SO4 + H2O SO3 + 2Na+ + 2OH− = 2Na+ + SO42− + H2O SO3 + 2OH− = SO42− + H2O FeCl2 + 2NaOH= Fe(OH)2↓ + 2NaCl Fe2+ + 2Cl- + 2Na+ + 2OH-=Fe(OH)2↓ + 2Na+ +2Cl- Fe2+ + 2OH-=Fe(OH)2  

Answer 2

Reactants for the Reaction with Sulfur(IV) Oxide

Sulfur(IV) oxide can react with various substances. Based on the provided search snippets, the following substances can react with sulfur(IV) oxide:

1. Aluminum2. Water3. Sodium hydroxide (NaOH)4. Barium hydroxide (Ba(OH)2)

Balanced Chemical Equations for the Reactions

The balanced chemical equations for the reactions of sulfur(IV) oxide with the mentioned substances are as follows:

1. Aluminum (Al): ``` 3SO2 + 2Al → Al2O3 + 3SO2 ```

2. Water (H2O): ``` SO2 + H2O → H2SO3 ```

3. Sodium hydroxide (NaOH): ``` SO2 + 2NaOH → Na2SO3 + H2O ```

4. Barium hydroxide (Ba(OH)2): ``` SO2 + Ba(OH)2 → BaSO3 + H2O ```

These balanced chemical equations represent the reactions of sulfur(IV) oxide with the specified substances.

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