Question

ПОМОГИТЕ ОЧЕНЬ СРОЧНО!!! Нужно решить хим. цепочку превращений: C-> CO2-> CaCO3-> CaCl2-> CaCO3-> CO2-> Na2CO3. Решить задачу: какой объём водорода (н.у.) потребуется для получения аммиака, если его выход составляет 96%?

Answer 1

Вот уравнение , задачу не знаю как решать

Answer 2

Chemical Reactions:

The given chemical reactions are as follows: 1. C -> CO2 2. CO2 -> CaCO3 3. CaCO3 -> CaCl2 4. CaCl2 -> CaCO3 5. CaCO3 -> CO2 6. CO2 -> Na2CO3

Calculating the Volume of Hydrogen Gas:

To calculate the volume of hydrogen gas required to produce ammonia, we need to determine the stoichiometry of the reaction and use the given information about the ammonia yield.

The balanced equation for the production of ammonia (NH3) from hydrogen gas (H2) is: N2 + 3H2 -> 2NH3

From the balanced equation, we can see that 3 moles of hydrogen gas are required to produce 2 moles of ammonia.

Given that the yield of ammonia is 96%, we can calculate the amount of ammonia produced from a given amount of hydrogen gas.

Let's assume we have x moles of hydrogen gas. According to the stoichiometry of the reaction, we can write the following equation:

(2/3) * x = 0.96 * 2

Simplifying the equation, we find:

x = (0.96 * 2 * 3) / 2

x = 2.88 moles of hydrogen gas

To convert moles of hydrogen gas to volume at standard temperature and pressure (STP), we can use the ideal gas law:

PV = nRT

Where: P = pressure (1 atm at STP) V = volume n = number of moles R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (273 K at STP)

Rearranging the equation, we get:

V = (n * R * T) / P

Substituting the values, we have:

V = (2.88 * 0.0821 * 273) / 1

V ≈ 63.3 liters

Therefore, approximately 63.3 liters of hydrogen gas at STP would be required to produce ammonia with a 96% yield.

Please note that this calculation assumes ideal conditions and may not account for other factors that could affect the reaction.