Question

при обработке серной кислотой 1т фосфорита,содержащего 62% фосфата кальция,было получено 910,8 кг суперфосфата ( Cа(H2PO4)2 ). Определить выход суперфосфата в процентах по отношению к теоретическому.

Answer 1

Ca3(PO4)2 + 2H2SO4 = Ca(H2PO4)2 + 2CaSO4

m(Ca3(PO4)2 = m(фосфорита)*W(Ca3(PO4)2) = 1000*0,62 = 620 кг

n(Ca3(PO4)2) = m(Ca3(PO4)2)/M(Ca3(PO4)2) = 620/310 = 2 кмоль

суперфосфат представляет собой смесь дигидрофосфата кальция и сульфата кальция - Ca(H2PO4)2 + 2CaSO4.

По уравнению n(Ca3(PO4)2) = n(Ca(H2PO4)2+ 2CaSO4 ) = 2 кмоль

m(Ca(H2PO4)2 + 2CaSO4) = n(Ca(H2PO4)2 + 2CaSO4 )*M(Ca(H2PO4)2 + 2CaSO4) = 2*506 = 1012 кг - это теоретическая масса.

выход = m(практическая)/m(теоретическую) = 910,8/1012 = 0,9, в процентах - 90%.

 

Answer 2

Calculating the Percentage Yield of Superphosphate

When processing 1 ton of phosphorite with 62% calcium phosphate content using sulfuric acid, 910.8 kg of superphosphate (Ca(H2PO4)2) was obtained. We need to determine the yield of superphosphate as a percentage of the theoretical yield.

To calculate the percentage yield, we can use the following formula:

Percentage Yield = (Actual Yield / Theoretical Yield) * 100%

First, let's calculate the theoretical yield of superphosphate.

The molar mass of phosphorite (Ca3(PO4)2) is approximately 310.18 g/mol, and the molar mass of superphosphate (Ca(H2PO4)2) is approximately 234.05 g/mol.

Using the given information, we can calculate the theoretical yield of superphosphate:

Theoretical Yield = (Mass of phosphorite) * (Percentage of calcium phosphate) * (Molar mass of superphosphate / Molar mass of phosphorite)

Theoretical Yield = 1000 kg * 0.62 * (234.05 g/mol / 310.18 g/mol)

Now, we can calculate the percentage yield using the actual yield of 910.8 kg:

Percentage Yield = (910.8 kg / Theoretical Yield) * 100%

Let's calculate the theoretical yield and then the percentage yield.