Question

Вычислить массу соли Na2SO4, которая образуется при взаимодействии H2SO4 с 50г NaOH. выход продукта реакции принять равным 80% от теоретически возможного

Answer 1

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Answer 2

Calculation of the Mass of Na2SO4 Formed

To calculate the mass of Na2SO4 formed when H2SO4 reacts with 50g of NaOH, we need to consider the balanced chemical equation for the reaction. The balanced equation is as follows:

2NaOH + H2SO4 -> Na2SO4 + 2H2O

From the equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4 to produce 1 mole of Na2SO4.

To find the number of moles of NaOH, we can use the formula:

moles = mass / molar mass

The molar mass of NaOH is 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol.

Therefore, the number of moles of NaOH is:

moles of NaOH = 50 g / 39.00 g/mol = 1.28 mol

Since the reaction has a 1:1 stoichiometric ratio between NaOH and Na2SO4, we can conclude that 1.28 moles of NaOH will produce 1.28 moles of Na2SO4.

To find the mass of Na2SO4, we can use the formula:

mass = moles * molar mass

The molar mass of Na2SO4 is 22.99 g/mol + 32.07 g/mol + (4 * 16.00 g/mol) = 142.04 g/mol.

Therefore, the mass of Na2SO4 formed is:

mass of Na2SO4 = 1.28 mol * 142.04 g/mol = 181.63 g

However, it is mentioned that the yield of the reaction is 80% of the theoretical yield. Therefore, we need to multiply the calculated mass by 80% to find the final mass of Na2SO4:

final mass of Na2SO4 = 181.63 g * 0.80 = 145.30 g

Therefore, the mass of Na2SO4 formed when H2SO4 reacts with 50g of NaOH, with an 80% yield, is approximately 145.30 grams.