Question

Сколько грамов воды и сульфата натрия нужно взять чтобы приготовить 10 % раствора

Answer 1

80 (воды)+10 (растворимого в-ва)=90 г раствора
10:100*100%=10%

Answer 2

Preparing a 10% Solution of Sodium Sulfate

To prepare a 10% solution of sodium sulfate, we need to determine the amount of water and sodium sulfate required. Let's calculate the quantities based on the given information.

Calculating the Amount of Water and Sodium Sulfate

The calculation involves determining the mass of water and sodium sulfate needed to prepare the 10% solution.

Based on the provided information, the mass of water (H2O) is given as 300, and the mass of sodium sulfate (Na2SO4) is given as 15.

Using the formula for concentration (cB = nB / V = mB / (MB * V)), where cB is the concentration, nB is the amount of substance, V is the volume, mB is the mass, and MB is the molar mass, we can calculate the required amounts.

From Source the molar mass of Na2SO4 is 142.04 g/mol.

Calculation

- Mass of water (H2O) = 300g - Mass of sodium sulfate (Na2SO4) = 15g - Molar mass of Na2SO4 = 142.04 g/mol

Using the formula cB = nB / V = mB / (MB * V), we can calculate the required amounts.

- For water (H2O): - cB = 10% = 0.1 - V = 300g - mB = ? - MB = 18.01528 g/mol (molar mass of water)

Solving for mB: mB = cB * MB * V mB = 0.1 * 18.01528 * 300 mB ≈ 54.05g

- For sodium sulfate (Na2SO4): - cB = 10% = 0.1 - V = 15g - mB = ? - MB = 142.04 g/mol (molar mass of sodium sulfate)

Solving for mB: mB = cB * MB * V mB = 0.1 * 142.04 * 15 mB ≈ 213.06g

Conclusion

To prepare a 10% solution of sodium sulfate, we need approximately 54.05 grams of water and 213.06 grams of sodium sulfate.