Question

4) Расставьте коэффициенты методом электронного баланса в реакции между: цинком и азотной разбавленной кислотой

Answer 1

4Zn + 10HNO3(разб., гор.) = 4Zn(NO3)2 + N2O↑ + 5H2O

Answer 2

Balancing the Reaction between Zinc and Dilute Nitric Acid using the Electron Balance Method

To balance the reaction between zinc and dilute nitric acid using the electron balance method, we need to consider the oxidation and reduction half-reactions and balance the number of electrons transferred in each half-reaction.

1. Oxidation Half-Reaction: - Zinc undergoes oxidation, losing electrons to form zinc ions. - The balanced oxidation half-reaction is: ``` Zn(s) → Zn^2+(aq) + 2e^- ```

2. Reduction Half-Reaction: - Nitric acid is reduced, gaining electrons to form nitrogen oxides. - The balanced reduction half-reaction is: ``` 2H^+(aq) + 2e^- + 2HNO3(aq) → N2O(g) + 3H2O(l) ```

3. Balancing the Number of Electrons: - To balance the number of electrons transferred in both half-reactions, we need to multiply the oxidation half-reaction by 2: ``` 2Zn(s) → 2Zn^2+(aq) + 4e^- ```

4. Overall Balanced Reaction: - Now, we can add the two half-reactions together to obtain the balanced overall reaction: ``` 2Zn(s) + 2H^+(aq) + 2HNO3(aq) → 2Zn^2+(aq) + N2O(g) + 3H2O(l) ```

The balanced reaction between zinc and dilute nitric acid using the electron balance method is: ``` 2Zn(s) + 2H^+(aq) + 2HNO3(aq) → 2Zn^2+(aq) + N2O(g) + 3H2O(l) ```