Question

РЕБЯТ, РЕШИТЕ ПОЖАЛУЙСТА.Определить в пробирках вещества и написать уравнение молекулярное полное ионное и краткое ионное уравнение.NaClNaOHNa2SO4

Answer 1

NaCl + AgNO3 = Ag Cl  + NaNO3     или индикатором
NaOH +СuSO4 = Cu(OH)2 + Na2SO4    или индикатором
Na2SO4  + BaCl2 = BaSO4 + 2NaCl

 

Answer 2

Identification of Substances in the Test Tubes

To identify the substances in the test tubes, we need to analyze the given compounds: NaCl, NaOH, and Na2SO4.

1. NaCl: Sodium chloride is a common salt that is highly soluble in water. It is composed of sodium ions (Na+) and chloride ions (Cl-). When dissolved in water, it dissociates into these ions.

2. NaOH: Sodium hydroxide is a strong base that is also highly soluble in water. It consists of sodium ions (Na+) and hydroxide ions (OH-). Similar to NaCl, NaOH dissociates into its constituent ions when dissolved in water.

3. Na2SO4: Sodium sulfate is a salt that is moderately soluble in water. It is composed of sodium ions (Na+) and sulfate ions (SO4^2-). When dissolved in water, it also dissociates into these ions.

Molecular, Complete Ionic, and Net Ionic Equations

Now, let's write the molecular, complete ionic, and net ionic equations for the given substances.

1. NaCl: - Molecular Equation: NaCl(aq) → Na+(aq) + Cl-(aq) - Complete Ionic Equation: NaCl(aq) → Na+(aq) + Cl-(aq) - Net Ionic Equation: No reaction occurs since NaCl is already fully dissociated in water.

2. NaOH: - Molecular Equation: NaOH(aq) → Na+(aq) + OH-(aq) - Complete Ionic Equation: NaOH(aq) → Na+(aq) + OH-(aq) - Net Ionic Equation: No reaction occurs since NaOH is already fully dissociated in water.

3. Na2SO4: - Molecular Equation: Na2SO4(aq) → 2Na+(aq) + SO4^2-(aq) - Complete Ionic Equation: Na2SO4(aq) → 2Na+(aq) + SO4^2-(aq) - Net Ionic Equation: No reaction occurs since Na2SO4 is already fully dissociated in water.

In summary, the molecular equations for NaCl, NaOH, and Na2SO4 are the same as their complete ionic equations because these compounds are already fully dissociated in water. Therefore, no net ionic equations can be written for these substances.

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